Question

Find the distance, c, between (4, 7) and (11, –1) on the coordinate plane. Round to the nearest tenth if necessary.

Answer 1

To find the distance between two points on a coordinate plane, we can use the distance formula:

d = √((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the two points, and d is the distance between them.

In this case, the two points are (4, 7) and (11, -1) , so we have:

d = √((11 - 4)^2 + (-1 - 7)^2)

d = √((7)^2 + (-8)^2)

d = √(49 + 64)

d = √113

Therefore, the distance between the two points on the coordinate plane is c = √113 (approximately 10.6)

You can round to the nearest tenth, so the distance c = 10.6.

Answer 2

• c = 10.6 units

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Use the distance formula to find the distance between the given points:

• 
  `c = √((x_2-x_1)^2+(y_2-y_1)^2)`

Substitute coordinates and calculate:

• 
  `c = √((11-4)^2+(-1-7)^2) =√(7^2+(-8)^2) =√(49+64) =√(113) =10.6`