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How many grams of NH3 can be produced from 10.8 g of H2
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How many grams of NH3 can be produced from 10.8 g of H2

User Rajh
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Answer:

Balanced equation is N2 + 3H2 ==> 2NH3

moles of N2 = 2.60 g x 1 mole/28 g = 0.0929 moles N2

grams H2 needed = 0.0929 moles N2 x 3 moles H2/mole N2 x 2 g/mole = 0.557 g H2 neede

Step-by-step explanation:

User Jesusita
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