Answer:
Step-by-step explanation:
NH3 + 3O2 -> NO + 2H2O
The balanced equation for the reaction of NH3 and O2 to form NO and H2O is:
4 NH3 + 5 O2 -> 4 NO + 6 H2O
From the balanced equation, we can see that for every 4 moles of NH3 that react, 6 moles of H2O are formed.
To find out how many grams of H2O are formed from 34.7 g of NH3, we can first convert the mass of NH3 to moles using the formula:
moles = mass/molar mass
The molar mass of NH3 is 17.03 g/mol.
So, 34.7 g of NH3 is equal to 34.7 g/17.03 g/mol = 2.04 moles of NH3
If 4 moles of NH3 react, 6 moles of H2O are formed.
So, if 2.04 moles of NH3 react, 2.04 moles/4 moles * 6 moles = 2.04 moles/4 * 6 moles = 3.06 moles of H2O are formed.
To find out the mass of 3.06 moles of H2O, we use the formula:
mass = moles * molar mass
The molar mass of H2O is 18.02 g/mol.
so, 3.06 moles of H2O weighs 3.06 moles * 18.02 g/mol = 55.18 g
In conclusion, 55.18 g of H2O are formed from the reaction of 34.7 g of NH3