Question

15. How many grams of water would be required to absorb 2000 J of heat with a

temperature change of only 5°C ? (the specific heat of water is 4.18 J/g°C)
q=mcAT

Answer 1

Answer: m = 95.7 g

Step-by-step explanation:

Use the equation q = m x Cs x delta T

Step 1: Identify what was provided in the problem.

q = 2000 J

m = ? (this is what we need to find)

Cs = 4.18 J/g °C

delta = 5°C

Step 2: Place known values into the equation.

q = m x Cs x delta T

2000 J = m x (4.18 J/g °C) x 5°C

Step 3: Isolate m by multiplying both sides of the equation by (4.18 J/g °C) x 5°C.

2000 J/(4.18 J/g °C) x 5°C = m

Step 4: Solve for m.

2000 J/(4.18 J/g °C) x 5°C = m

Note that J and °C units cancel and you are left with g only.

m = 95.7 g