Answer:
100 g
Step-by-step explanation:
Numerical problems based On Mole Concept
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3). Solution — Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. of moles of CaCO3 = No. of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No.