Question

Joe is twice as old as Gabriel and Gabriel is five years older than Matthew.

If the sum of their age is 63, how old are they?

Answer 1

Gabriel=17

Joe=34

Matthew=12

Explanation:

Let Gabriel be: x. Then, Joe would be 2x and Matthew would we x-5. The total is 63, so we can make the equation:

x+2x+x-5=63

x+2x+x=68

4x=68

x=17

So Gabriel would be 17(x), Joe would be 34(2x), and Matthew would be 12(x-5).

Hope this helps!

Answer 2

Let's use x to represent Matthew's age.

If Gabriel is five years older than Matthew, Gabriel's age is x + 5.

And Joe is twice as old as Gabriel, so Joe's age is (x + 5) * 2 = 2x + 10.

We know that the sum of their ages is 63, so we can set up the equation:

x + (x + 5) + (2x + 10) = 63

4x + 15 = 63

4x = 48

x = 12

So, Matthew is 12 years old, Gabriel is 12 + 5 = 17 years old and Joe is 2 * 17 = 34 years old.