Question

ON A SOFTBALL FIELD (SHAPE OF A

SQUARE), THE DISTANCE FROM HOME
PLATE TO FIRST BASE IS 65 YARDS, HOW
FAR DOES THE CATCHER THROW THE
BALL FROM HOME PLATE TO SECOND
BASE?
DISTANCE OF THROW FROM HOME PLATE
I
TO SECOND BASE IS

Don’t really get this, help anyone ??

Answer 1

Answer: 91.92 yards

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Step-by-step explanation:

Draw a square that is tilted on one side (so it resembles a diamond shape). Each side of the square is 65.

Draw a vertical line through the top and bottom vertices of the square to connect home plate (bottom) to 2nd base (top). This forms 2 right triangles that are mirror clones of each other, aka they are congruent triangles.

Focus on one of those right triangles. The legs are a = 65 and b = 65. The hypotenuse is unknown which I'll call c.

Use the pythagorean theorem to find c.

`a^2 + b^2 = c^2\\\\65^2 + 65^2 = c^2\\\\4225 + 4225 = c^2\\\\8450 = c^2\\\\c^2 = 8450\\\\c = √(8450)\\\\c \approx 91.92388\\\\c \approx 91.92\\\\`

The distance from home to 2nd is roughly 91.92 yards

Side note: 91.92 yards = 91.92*3 = 275.76 feet