Question

What are the zeros of the quadratic function f(x) = 6x² + 12x-7?

O x=-1-√3 and x = -1 +
O x=-1-and x = -1+√73
=-1-√√ and x = -1 +₁
0 x = -1
13
6
0 x = -1/ and x = -1 +
76
1+√/

Answer 1

The zeros of the quadratic function f(x) = 6x² + 12x-7 are x = -1±√(12+24)/(2*6) = -1±√(36/12) = -1±√3

Explanation:

A quadratic function is a polynomial function of the form f(x) = ax² + bx + c, where a, b, and c are constants and a is not equal to 0. The zeros of a quadratic function are the values of x that make the function equal to zero. To find the zeros of f(x) = 6x² + 12x - 7, we can set the function equal to zero and solve for x.

f(x) = 6x² + 12x - 7 = 0

To solve for x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

By substituting the value of a, b and c in the quadratic formula we will get

x = (-12 ± √(12² - 46-7)) / (2*6) = (-12 ± √(144 + 84)) / 12

x = (-12 ± √(228)) / 12

x = (-1 ± √(228))/6 = -1±√(36/12) = -1±√3

So the roots of the equation is x = -1±√3