Answer:
it takes 64 J of heat energy to heat 2 kg of lead from 265 K to 315 K.
Step-by-step explanation:
To find out how much heat is needed to heat 2 kg of lead from 265K to 315 K, we can use the formula for specific heat capacity, which is:
q = mcΔT
Where:
q = heat energy (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
The specific heat capacity of lead is 0.128 J/g°C. we need to convert it to J/kg°C
So, the heat energy needed is:
q = (2 kg)(0.128 J/kg°C)(315 K - 265 K)
q = (2 kg)(0.128 J/kg°C)(50 K)
q = 64 J
Therefore, it takes 64 J of heat energy to heat 2 kg of lead from 265 K to 315 K.