Question

A car accelerates from 16 m/s to 23 m/s in 6.0 s

What was its acceleration assuming it is constant?
Express your answer using two significant figures.

How far did it travel in this time?
Express your answer using two significant figures.

Answer 1

Acceleration = 1.2m/s²

distance = 21m

Step-by-step explanation:

`acceleration = \: (v2 - v1)/(t)`

Where V1 is the initial velocity

" V2 is the Final Velocity

and t is the time

Substituting you have

`a = \frac{(23 - 16)ms {}^( - 1) }{6s}`

a = 7/6m/s²

a = 1.16666m/s²

a ≈ 1.2m/s² to 2 s.f figures

The distance covered will be

`s = ut + (1)/(2) at {}^(2)`

u = 0m/s

a = 1.1666...m/s²

s = ?

Substituting you have

`s = (0 * 6) + (1)/(2) * 1.1666 * 6 {}^(2)`

`s = (1)/(2) * 41.9976`

`s = 20.9988m`

s ≈ 21m to 2 s.f figures