Question

Please help ASAP! Question is in the image is below.

Answer 1

Answer: when x=0 f(0)=1/2

when x=-3 f(-3)= 2

Answer 2

`\huge\text{Hey there!}`

`\huge\textsf{Part I}`

`\huge\textbf{When \boxed{\bf x = 0}}`

`\mathsff(x) = (`

`\mathsff(x) = (`

`\mathsff(x) = (`

`\mathsf{f(x) = (1)/(2) + 2}`

`\mathsf{f(x) = (1)/(2)* 1 + (2)/(1)*2}`

`\mathsf{f(x) = (1)/(2)* (1)/(1) + (2)/(1)* (2)/(2)}`

`\mathsf{f(x) = (1*1)/(2*1) + (2*2)/(1*2)}`

`\mathsf{f(x) = (1)/(2) + (4)/(2)}`

`\mathsf{f(x) = (1 + 4)/(2 + 0)}`

`\mathsf{f(x) = (5)/(2)}`

`\mathsf{f(x) = 2(1)/(2)}`

`\huge\textsf{Part II}`

`\huge\textbf{When }\huge\boxed{\rm{\bf x = -3}}`

`\mathsf)/(2) + 2`

`\mathsf)/(2) + 2`

`\mathsf)/(2) + 2`

`\mathsff(x) = (`

`\mathsf{f(x) = (4)/(2) + 2}`

`\mathsf{f(x) = (4)/(2) + (2)/(1)}`

`\mathsf{f(x) = (4)/(2)* 1 + (2)/(1)*2}`

`\mathsf{f(x) = (4)/(2)* (1)/(1) + (2)/(1)*(2)/(2)}`

`\mathsf{f(x) = (4*1)/(2*1)+ (2*2)/(1*2)}`

`\mathsf{f(x) = (4)/(2)+ (4)/(2)}`

`\mathsf{f(x) = (4 + 4)/(2 + 0)}}`

`\mathsf{f(x) = (8)/(2)}}`

`\mathsf{f(x) = (8/2)/(2/2)}}`

`\mathsf{f(x) = (4)/(1)}}`

`\mathsf{f(x) = 4}`

`\huge\text{Therefore, your answer(s) should be:}`

`\huge\boxed{\mathsf{f(x) = (5)/(2); f(x) = 2(1)/(2)}}}\huge\checkmark\\\\\huge\text{Either of those should work because they}\\\huge\text{are practically the \underline{same thing }\huge\boxed{\uparrow}}\\\\\\\\\huge\boxed{\mathsf{f(x) = 4}}\huge\checkmark`

~
`\frak{Amphitrite1040:)}`