Question

Solve the following problems

1. Solve the electric force of two +10μC which has a distance of 5 cm. What is the interaction?
2. Solve the electric force of a -5.6μC and a 10.6nC charges separated 7 m from one another. What is the interaction?
3. Solve the electric force of two -7.8 μC which has a distance of 2.3 cm. What is the interaction?

Answer 1

1. The electric force between two charges is given by the equation:

F = k * (q1 * q2) / r^2

where F is the force, k is the Coulomb's constant (8.99 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between the charges.

q1 = 10e-6 C and q2 = 10e-6 C

r = 5 x 10^-2 m

F = 8.99 x 10^9 N * m^2 / C^2 * (10e-6 C * 10e-6 C) / (5 x 10^-2 m)^2

F = 8.99 * 10^9 * 10^-12 / 25 * 10^-4

F = 0.36 N

2. The electric force between two charges is given by the equation:

F = k * (q1 * q2) / r^2

where F is the force, k is the Coulomb's constant (8.99 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between the charges.

q1 = -5.6e-6 C and q2 = 10.6e-9 C

r = 7m

F = 8.99 x 10^9 N * m^2 / C^2 * (-5.6e-6 C * 10.6e-9 C) / (7 m)^2

F = -4.4*10^-5 N

3. The electric force between two charges is given by the equation:

F = k * (q1 * q2) / r^2

where F is the force, k is the Coulomb's constant (8.99 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between the charges.

q1 = -7.8e-6 C and q2 = -7.8e-6 C

r = 2.3 x 10^-2 m

F = 8.99 x 10^9 N * m^2 / C^2 * (-7.8e-6 C * -7.8e-6 C) / (2.3 x 10^-2 m)^2

F = 8.99 * 10^9 * 7.8^2 10^-12 / (2.310^-2)^2

F = 4.58 N

In all three problems the interaction is repulsive because the force is positive.