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What is the probability that Louisville defeat Brianna at one game of rock paper scissors
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What is the probability that Louisville defeat Brianna at one game of rock paper scissors

User MojoFilter
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2 Answers

2 votes
Answer:
1/2
Explanation:
Let 'E' be the event where Louisville defeat Brianna at one game of rock paper scissors
Total number of outcomes- 2 (either Louisville will win or lose)
Number of favorable outcomes -1 (Louisville will win)
Therefore;
P(E) = favorable outcomes / total outcomes = 1/2
User Wilson
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3 votes

Answer:

1/3 chance to win, 1/3 chance to tie, 1/3 chance to

User Denis Ryabov
by
7.7k points
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