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6. What is the specific heat capacity of a substance if 2.41x10* J are needed to

change the temperature of 105.0 g of it from 25.0°C to 75.0°C?

User Jan Marek
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1 Answer

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Answer: 4.59 x 10^-3 J/(g x degrees Celsius) = Cs

Step-by-step explanation:

Use the equation q = m x Cs x delta T to find the specific heat capacity of the substance.

q = heat in joules

m = mass of substance in grams

Cs = specific heat capacity in J/(g x degrees Celsius)

delta T = change in temperature in degrees Celsius

Step 1: Identify all quantities given in the problem.

q = 2.41 x 10 J

Note: Not sure if this number was supposed to have an exponent or not. I used what was posted by the person asking the question.

m = 105.0 g

Cs = variable we are trying to find

delta T = Temp. final – Temp. initial = 75.0 degrees Celsius – 25.0 degrees Celsius = 50.0 degrees Celsius

Step 2: Place all known quantities into the equation.

q = m x Cs x delta T

2.41 x 10 J = 105.0 g x Cs x 50.0 degrees Celsius

Step 3: Isolate the unknown variable, in this case Cs.

2.41 x 10 J = (105.0 g x Cs x 50.0 degrees Celsius) / (105.0 g x 50.0 degrees Celsius)

When you divide to isolate Cs, the units of grams and degrees Celsius cancel on the right side of the equation.

2.41 x 10 J / (105.0 g x 50.0 degrees Celsius) = Cs

4.59 x 10^-3 J/(g x degrees Celsius) = Cs

User Mohitt
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