21.2k views
5 votes
What is the mass of 4.55 x 10^28 atoms of vanadium

User Mr Talha
by
8.3k points

1 Answer

1 vote

Answer:

The mass of 4.55 x 10^28 atoms of vanadium is 2.31 x 10^30 u or 2.31 x 10^30 grams.

Step-by-step explanation:

To calculate the mass of a given number of atoms, we need to know the atomic mass of the element in question, which is the mass of one atom of that element. The atomic mass of vanadium is approximately 50.94 u (unified atomic mass unit)

To calculate the mass of 4.55 x 10^28 atoms of vanadium, we can use the formula:

mass = (number of atoms) x (atomic mass)

mass = (4.55 x 10^28 atoms) x (50.94 u)

mass = 2.31 x 10^30 u

The mass of 4.55 x 10^28 atoms of vanadium is 2.31 x 10^30 u or 2.31 x 10^30 grams.

It's important to note that this is a very large number, expressing the mass in kilograms or even tons would be more practical.

User Mzjn
by
7.5k points