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Segment AB is tangent to ⊙T at B. What is the radius of ⊙T? Triangle ABT where T forms the centre of a circle. B is a point on the circumference of the circle. The side AT intersects the circumference at the point C. AC equals 25 and Ab equals 45.

Segment AB is tangent to ⊙T at B. What is the radius of ⊙T? Triangle ABT where T forms-example-1
User Gurvan
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1 vote

Answer:

28

Explanation:

AB and TB are perpendicular because the tangent and radius are perpendicular. So you have a right triangle. Triangle ABT is a right triangle.

Also, TB is a radius of the circle, but so is TC. They are the same length.

Use Pythagorean Theorem to solve this problem.

AB^2 + TB^2 = AT^2

see image.

Segment AB is tangent to ⊙T at B. What is the radius of ⊙T? Triangle ABT where T forms-example-1
User Rami Nour
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8.6k points

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