Question

A 65.2 kg base runner begins his slide into second base while moving at a speed of 4.93 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s². What is the magnitude of the mechanical energy lost due to friction acting on the run- ner? Answer in units of J.​

Answer 1

about 792 J

Step-by-step explanation:

You want the mechanical energy lost by a 65.2 kg base runner who slides into second base from a speed of 4.93 m/s, reaching the base with a speed of 0.

Kinetic energy

The runner's kinetic energy is ...

KE = 1/2mv²

KE = 1/2(65.2 kg)(4.93 m/s)² = 792.33974 J

As the runner slides into second base, his speed decreases to zero, so all of his kinetic energy is lost to friction.

The energy lost to friction is about 792 J.