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Write an equation in slope intercept form passing through the point (-10,1) and parallel to the line 10x+5y=15

User Nlawalker
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1 Answer

5 votes

Answer: y=-2x-19

Step-by-step explanation:

First, you should arrange the equation in the form of y=mx+c (that is the standard form of this type of equation)

10x+5y=15

5y=-10x+15


(5y)/(5) =(-10x)/(5)+(15)/(5)

y=-2x+3 (now you got the equation in the simple form)

now you should substitute the given point (-10,1) into the simplified equation

y= 1 & x=-10

1=-2(-10)+c (the y-intercept must be taken as c )

c= 1 - 20

c= -19

therefore the equation will be : y=-2x-19

it will be the same gradient as the other line for this line too as the lines are parallel, you should only find the y-intercept. The gradient of the other line will stay the same as long as they are parallel lines.

User JJaun
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