1 Answer

Jaime · Answer 1 · 2024-04-30T12:10:59+0000

Answer:

y = 1/80

Explanation:

$\sf\frac {5}{8y} + 7 = (3)/(4y)- 3$

Substract 7 from both sides

$\sf\frac {5}{8y} + 7 - 7 = (3)/(4y)- 3 - 7$

Calculate

$\sf\frac {5}{8y} = (3)/(4y)-10$

Substract 3/4y from both sides

$\sf\frac {5}{8y} - (3)/(4y) = (3)/(4y) - (3)/(4y) -10$

Calculate

$\sf\frac {5}{8y} -(3)/(4y)= -10$

L.C.M = 32y²

$\sf \frac{−4y}{ {32y}^(2) } = -10$

-4y/32y² Divide further

$\sf ( - 4)/( 32y ) = -10$

Divide further

$\sf ( - 1)/( 8y ) = -10$

Cross - multiply

$\sf \: 8y * - 10 = - 1$

Multiply

$\sf \: - 80y = - 1$

Divide both sides by -80y

$\sf \: ( - 80y)/( - 80) = - ( - 1)/( - 80)$

Calculate

$\sf \: y = (1)/(80)$

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