116k views
5 votes
What is the 18th term of the arithmetic sequence where a3 = −6 and a12 = −3?

Group of answer choices

0

1

−3

−1

1 Answer

2 votes

Step-by-Step Step-by-step explanation:

3rd term (a3) = -6

12th term (a12) = -3

We know, nth term of an AP = a1 + (n - 1)d, where d = common difference

a3 = a + (3-1)d = a + 2d = -6...(I)

a12 = a + (12-1)d = a + 11d = -3..(II)

Subtracting (II) from (I), we have

2d - 11d = -6 + 3

=> -9d = -3

=> d = 1/3

Therefore, a + 2×1/3 = -6

=> a + 2/3 = -6

=> a = -6-2/3 = -20/3

Therefore, 18th term

= a + (18-1)d

= -20/3 + 17/3

= -3/3

= -1

Answer:

-1

Hope it helps.

If you have any query, feel free to ask.

User Rujul Gandhi
by
7.1k points