Answer:
16Ag +S8 --> 8Ag2S
Step-by-step explanation:
You know that you are starting out with 8 sulfer's on the reactant side, so there must be an equal amount on the product side. So, to get 8 sulfer's on the product side we multiply the entire (Ag2S) by 8 to get 8Ag2S. Now on the reactant and product side we have an equal amount of sulfer. However, the product side has 16 silvers. To balance this out, on the reactant side we multiply the number of Ag by 16 to get 16 Ag ont he reactant and product sides. Now the reactant and product sides have the same number of each element :)