The length of rectangle :10 feet
The width of rectangle : 4 feet
Given
perimeter of the rectangle :28 feet
let width of the rectangle be :x
and length of the rectangle be : 6+x (as per given condition)
therefore
perimeter = 2(length +width)
28 = 2(6+x+x)
28 = 2(6+2x)
28 = 12+4x
28-12 = 4x
16 = 4x
x = 4
as width of rectangle is : 4
similarly length : 6+x
6+4
:10
The dimensions of the rectangle are : length =10
width = 4
verification :
perimeter =2(l+w)
28 = 2(10+4)
28 = 28