Given
2a-5b= -19 (equation1)
3a+5b = 9 (equation2)
now add both equation 1 and equation 2
2a-5b=-19
3a+5b= 9
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5a = -10 (as +5b and -5b get canceled)
5a = -10
a = -2
(substitute in equation 2 or in equation 1)
3(-2)+ 5b= 9
-6 +5b =9
5b = 9+6
5b = 15
b= 3
therefore
a= -2
b= 3
verification:
2(-2)-5(3) = -19
-19 = -19
hence verified.