Question

Photo attached. Please help.

Answer 1

There is no real solution set for this equation

Explanation:

We have

`√(2x-1)+7=4`

Move 7 to the right side:

`√(2x-1)+7-7=4-7\\\\√(2x-1)=-3\\\\`

If we treat 2x - 1 as a function f(x) then we are getting

`√(f(x)) = -3\\\\`

But the square root of a function cannot be negative for real values of x

Hence there is no real solution set