A line that is perpendicular to the line y = -1/3x + 7 has a slope that is the negative reciprocal of -1/3 which is 3.
We know that the line intersects the point (4,2), so we can use this point and the slope to write the equation of the line in point-slope form:
y - y1 = m(x - x1)
where (x1, y1) is the point the line passes through, m is the slope, and y and x are the coordinates of any point on the line.
So the equation of the line that is perpendicular to y = −1/3x + 7 and intersects the point (4,2) is:
y - 2 = 3(x - 4)
Simplifying this, we get
y = 3x - 2
To convert this to the slope-intercept form we can rewrite it as
y = 3x + b
Therefore, the equation of the line that is perpendicular to y = −1/3x + 7 and intersects the point (4,2) is y = 3x - 2