Answer:
the probability of randomly selecting the chair and the vice chair is 10%.
Explanation:
There are a total of 5 members on the health services committee, and 2 of them will be chosen to serve as the chair and vice chair, respectively.
The probability of randomly selecting the chair out of the 5 members is 2/5, or 40%.
Once the chair is selected, there are 4 members remaining, and only one of them can serve as the vice chair. Therefore, the probability of randomly selecting the vice chair out of the remaining 4 members is 1/4, or 25%.
To find the probability of randomly selecting the chair and the vice chair, we need to multiply the individual probabilities of selecting each position, which is (2/5) * (1/4) = 2/20 = 1/10 = 10%.
So, the probability of randomly selecting the chair and the vice chair is 10%.