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Write the equation of a line perpendicular to y=2x−5 that passes through the point (2, -5) in slope-intercept form.

User Orionss
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To write the equation of a line that is perpendicular to y = 2x - 5, we need to find the slope of the new line.

As we know, the slope of a line perpendicular to y = 2x - 5 is the negative reciprocal of the slope of y = 2x - 5, which is -1/(2) = -1/2.

To find the equation of the line in slope-intercept form (y = mx + b), we can use the point (2, -5) and the slope of -1/2.

We know that the point (2, -5) belongs to the line, so we can substitute these values into the equation:

y = -1/2x + b

-5 = -1/2(2) + b

-5 = -1 + b

b = -4

So, the equation of the line in slope-intercept form is:

y = -1/2x -4

This is the equation of a line that is perpendicular to y = 2x - 5 and passes through the point (2, -5)

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