Question

How do you factor this problem by grouping?
4x∧3-3x∧2-28x+21

Answer 1

(x^2 - 7)(4x - 3)

Explanation:

first, we split the expression by grouping the first two terms in parentheses and the last two terms in parentheses. this gives us:

`(4x^(3)-3x^(2))(-28x+21)`

next, we factor out the GCF of each group. this gives us:

`x^(2)(4x-3)-7(4x-3)`

finally, all you have to do is take each factored-out term and put them together into a group/expression. the leftover expression from both groups is the same value, so you get:

`(x^(2)-7)(4x-3)`

hope this helped, good luck!