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5 votes
An airplane travels down a

runway for 4.0 seconds with an
acceleration of 9.0 m/s2. What
its change in velocity during
this
time?
Someone helpppp!!

User Amosmos
by
8.2k points

1 Answer

3 votes

Answer:

We can use the equation of motion of an object under constant acceleration to calculate the change in velocity during this time. The equation is:

Δv = at

Where:

Δv = change in velocity (m/s)

a = acceleration (m/s^2)

t = time (s)

Given that the acceleration of the airplane is 9.0 m/s^2 and the time it travels down the runway is 4.0 seconds we can substitute these values into the equation:

Δv = 9.0 m/s^2 * 4.0 s = 36 m/s

Therefore, the change in velocity of the airplane during this time is 36 m/s.

User Teetz
by
7.0k points