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What is the equation of a line that passes through the point (6,-8) and has a slope of -5/6

2 Answers

2 votes

Answer:

(6,-5)

Explanation:

(y-y1)=m(x-x1)

(y--8)=-5/6(x-6)

6y=-5x+2

User Sotsir
by
6.9k points
3 votes

Answer:

y = (-5/6)x - (5/3)

Explanation:

The equation of a line in point-slope form is y - y1 = m(x - x1) where (x1,y1) is a point on the line, and m is the slope of the line.

Given that the line passes through the point (6,-8) and has a slope of -5/6, the equation of the line is:

y - (-8) = (-5/6)(x - 6)

y + 8 = (-5/6)x + (-5/6) * 6

y = (-5/6)x - (5/3)

User Chintan S
by
7.8k points