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In ΔIJK, k = 1.9 inches, m∠J=59° and

m∠K=18°. Find the length of j, to the nearest 10th of an inch.

In ΔIJK, k = 1.9 inches, m∠J=59° and m∠K=18°. Find the length of j, to the nearest-example-1
User Rahpuser
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1 Answer

6 votes

Check the picture below.


\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin(18^o)}{1.9}=\cfrac{\sin(59^o)}{j}\implies j=\cfrac{1.9\sin(59^o)}{\sin(18^o)}\implies j\approx 5.3~in

Make sure your calculator is in Degree mode.

In ΔIJK, k = 1.9 inches, m∠J=59° and m∠K=18°. Find the length of j, to the nearest-example-1
User Russell Horwood
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