Answer: I am not sure about this but here you go
he overall displacement of the particle, δx, is equal to the final position of the particle minus its initial position. Since the initial and final velocities of the particle are given, the displacement can be calculated using the equation δx = vft - vit, where vf is the final velocity, vi is the initial velocity, and t is the time interval. In this case, δx = 18.0 m/s11.5 s - 29.0 m/s11.5 s = -131 m. Therefore, the overall displacement of the particle is -131 m.