Question

Suppose you are given a Stock Solution of 15.406 M hydrochloric acid. What volume of water must you add have ready to add your acid to (in mL) to prepare a solution with a hydrochloric acid molar concentration of 3.361 M and a volume of 372.510 mL? NOTE: When typing your answer below, round your answer to 3 decimal places. Show you work for part marks. Do not forget to upload your steps. Keep units according to the givens in the question.​

Answer 1

M1V1 = M2V2

where M1 and V1 are the molar concentration and volume of the stock solution, and M2 and V2 are the molar concentration and volume of the final solution. We can use this formula to find the volume of water that we need to add to the stock solution to prepare the final solution.

Plugging in the given values, we have:

15.406 M x V1 = 3.361 M x 372.510 mL

To solve for V1, we can divide both sides of the equation by 15.406 M:

V1 = 3.361 M x 372.510 mL / 15.406 M

V1 = 24.227 mL

Therefore, we need to add 24.227 mL of water to the stock solution of 15.406 M hydrochloric acid to prepare a solution with a hydrochloric acid molar concentration of 3.361 M and a volume of 372.510 mL.