Question

A 2. 0 kg toy car is released at the top of a frictionless track on the left and rolls off of the track from its right

side ramp. The car starts at a height of 0. 80 m, goes through a 0. 50 m diameter loop, and exits the ramp at a

height of 0. 25 m.

what is the change in the cars gravitational potential energy form A to B?

Answer 1

The change in the car's gravitational potential energy from A to B is -11.76 J.

Step-by-step explanation:

The change in the car's gravitational potential energy can be calculated by subtracting the initial potential energy from the final potential energy. The gravitational potential energy of an object is given by the equation PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

In this case, the initial potential energy (PEA) is given by mghA and the final potential energy (PEB) is given by mghB.

The change in gravitational potential energy (ΔPE) can be calculated as:

ΔPE = PEB - PEA = mghB - mghA

Substituting the given values, the change in the car's gravitational potential energy from A to B is:

ΔPE = (2.0 kg)(9.8 m/s²)(0.25 m) - (2.0 kg)(9.8 m/s²)(0.80 m)

ΔPE = -11.76 J