Answer:
2^1 = 2 -> last digit is 2
2^2 = 4 -> last digit is 4
2^3 = 8 -> last digit is 8
2^4 = 16 -> last digit is 6
2^5 = 32 -> last digit is 2
2^6 = 64 -> last digit is 4
2^7 = 128 -> last digit is 8
We can observe that the last digit follows a pattern of 2,4,8,6,2,4,8 and repeat.
Therefore, 2 to the power of 47 will have the same last digit as 2 to the power of (47 modulo 4) + 3
(47 mod 4) + 3 = 51 mod 4 = 3
The last digit of 2 to the power of 3 is 8
Therefore, the last digit of 2 to the power of 47 is 8.