Question

a woodpecker beak has a velocity of 7.49 m/s at impact. if it stops in a distance of 1.87 mm, find the average acceleration of the woodpecker's beak

Answer 1

Explanation: Average acceleration = (velocity/distance)

= Convert 1.87 to meters

1.87 / 1000 = 0.00187

(7.49 m/s / 0.00187 m)

= 3987.37 m/s²