Given,
Amount of sodium atoms = 46 grams
To find,
The total number of sodium atoms present in the given amount of sodium atoms.
We can simply solve this numerical problem by using the following process:
As per stoichiometry;
1 mole of any element contains Avogadro's number of atoms, that is, 6.022 x 10^23 atoms.
And, the molar mass of any element is equal to the atomic mass of the same element.
=> If the given amount of an element/compound is equal to its molar mass, then it contains 6.022 x 10^23 atoms/molecules.
=> Total number of atoms/molecules present in the given amount of the element/compound
= (total given mass)/(molar mass) x 6.022 x 10^23
Now,
the molar mass of sodium = 23 grams
Total number of sodium atoms present in the given amount of sodium atoms
= (total mass)/(molar mass) x 6.022 x 10^23
= 46 grams / 23 grams x 6.022 x 10^23
= 2 moles x 6.022 x 10^23
= 12.044 x 10^23 = 1.2044 x 10^24 atoms
Hence, 1.2044 x 10^24 sodium atoms are present in the given amount of sodium atoms.