Question

A car traveling at 60 mph can stop in a 48 m on a level Road determine the collision of friction between the tires and the road.

Answer 1

.763

Step-by-step explanation:

60 mi/hr = 26.82 m/s

Average velocity = 26.82/2 = 13.41 m/s

d = vt

48 = 13.41 t

t = 3.58 s

a = change in velocity/change in time

= 26.82 / 3.58 = 7.49 m/s^2

Ff = ma uf = Ff/ Fn = Ff/ mg

ma / mg = uf

a/g = uf

7.49 / 9.81 = coefficient of friction = .763