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15. Determine whether the statement is true or false. NOT MULTIPLE CHOICE!!
a. The graph of f^-1(x) is a reflection of the graph of f(x) over the line y = x.
b. if f^-1(x) is the inverse of f(x), then f(x) must be always be increasing.
c. The function y = x^2 has an inverse.
d. If a function has a y-intercept, then its inverse must also have a y-intercept.
e. If a function has a y-intercept, then its inverse must have an x-intercept.

User Galex
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1 Answer

6 votes

Answer:

a. True

b. False

c. False

d. False

e. True

Explanation:

a. True: The graph of f^-1(x) is a reflection of the graph of f(x) over the line y = x. This is because for any point (x,y) on the graph of f(x), the point (y,x) will be on the graph of f^-1(x), and vice versa.

b. False: The inverse function, f^-1(x) does not have to be always increasing. It depends on the original function, f(x) and its properties, A function could be increasing or decreasing, or it could be a combination of both, or none of them. A function which is strictly increasing is guaranteed to have a unique inverse, but that inverse function may or may not be increasing.

c.False: The function y = x^2 does not have an inverse function. Because it is not a one-to-one function. It is not injective, meaning that it maps multiple input values to the same output value, so it cannot be inverted.

d. False: If a function has a y-intercept, it does not mean that its inverse must also have a y-intercept. A y-intercept is a point at which a function crosses the y-axis, which corresponds to x = 0. However, the inverse function of a function will have its x and y coordinates swapped, so the inverse of a function that crosses the y-axis at a particular point will not cross the x-axis at the same point.

e. True: If a function has a y-intercept, it means that the function crosses the y-axis. But since the inverse function of a function will have its x and y coordinates swapped, the inverse of a function that crosses the y-axis at a particular point will cross the x-axis at the same point.

User DanieleAlessandra
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