Answer:
The five consecutive odd integers whose sum will be 85 are 13, 15, 17, 19, and 21.
Explanation:
To solve this problem, let's assume the first number is n.
Then the consecutive odd integers will be n+2, n+4, n+6, n+8
Thus we can write,
n+(n+2)+(n+4)+(n+6)+(n+8) = 85
In the next step add all the n's,
5n+20 = 85
Then transfer '20' from LHS to RHS,
5n = 85 - 20
5n = 65
Then in the next step '5' needs to be transferred to RHS,
n = 65÷5
n = 13
Therefore, n = 13
n+2 = 15
n+4 = 17
n+6 = 19
n+8 = 21
Thus the five consecutive odd integers are 13, 15, 17, 19, and 21.