137k views
1 vote
Find five consecutive odd integers whose sum is 85.

2 Answers

2 votes

Answer:

The five consecutive odd integers whose sum will be 85 are 13, 15, 17, 19, and 21.

Explanation:

To solve this problem, let's assume the first number is n.

Then the consecutive odd integers will be n+2, n+4, n+6, n+8

Thus we can write,

n+(n+2)+(n+4)+(n+6)+(n+8) = 85

In the next step add all the n's,

5n+20 = 85

Then transfer '20' from LHS to RHS,

5n = 85 - 20

5n = 65

Then in the next step '5' needs to be transferred to RHS,

n = 65÷5

n = 13

Therefore, n = 13

n+2 = 15

n+4 = 17

n+6 = 19

n+8 = 21

Thus the five consecutive odd integers are 13, 15, 17, 19, and 21.

User Maksim Sorokin
by
8.5k points
0 votes

Answer:

13+15+17+19+21 = 85

Explanation:

Hope you got it !

User Muhammad Hamza
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories