Question

An acute angle, θ, is in a right triangle such that sin of theta is equal to 2/5. What is the value of cot θ?

Answer 1

cotθ=√21/2

Explanation:

we have,

sinθ= 2/5= perpendicular/hypotenuse

here,

perpendicular=2

hypotenuse = 5

Now using Pythagorean theorem,

h^2 = p^2+ b^2

(5)^2 = 2^2 +b^2

b= √21

so,

cotθ= base/perpendicular = √21 /2

Hope you like the explanation.