Question

What is the equation of the line that passes through the point (−1,1)(−1,1) and has a slope of 5?

Answer 1

The equation of a line can be represented in the slope-intercept form, y = mx + b, where m is the slope of the line and b is the y-intercept.

Given that the line has a slope of 5 and passes through the point (-1,1) we can use the point-slope form of a linear equation, which is y - y1 = m(x - x1)

The point (-1,1) can be plugged into the equation:

y - 1 = 5(x + 1)

By simplifying and re-arranging the equation, we get:

y = 5x + 6

So the equation of the line that passes through the point (-1,1) and has a slope of 5 is: y = 5x + 6

Answer 2

y = 5x+6

Explanation:

Using the slope-intercept form of a line

y = mx+b where m is the slope and b is the y-intercept

y = 5x+b

Substitute the point into the line.

1 = 5(-1) +b

1+5 = b

6=b

The equation is

y = 5x+6