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A machine of efficiency 80% does 3000j of work. caculate the energy used in over function?​

User Yesse
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1 Answer

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The machine does 3000 J of work.

This is 80% of the energy that was put into the machine.

3000 J = 0.80 x (Input energy)

Divide both sides of the equation by 0.80 .

Input energy = 3000 J / 0.8

Input energy = 3750 J

User Liezel
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