There is one point of intersection on the graph of y = x² + 3x - 2 and y - x = 4
To find the point of intersection, we need to set the two equations equal to each other and solve for x and y.
y = x² + 3x - 2
y - x = 4
x² + 3x - 2 - x = 4
x² + 2x - 6 = 0
(x-3)(x+2)=0
x =3 or x=-2
When x = 3, we substitute it into the first equation y = x² + 3x - 2
y = 3² + 3(3) - 2
y = 9 + 9 - 2
y = 16
When x = -2, we substitute it into the first equation y = x² + 3x - 2
y = -2² + 3(-2) - 2
y = 4 -6 -2
y = -4
So the point of intersection is (3,16) or (-2,-4)
Hence there is only one point of intersection on the graph of y = x² + 3x - 2 and y - x = 4