So there are multiple ways to solve this problem, including: factoring, completing the square, and the quadratic formula. For this one, I’ll show you factoring.
Given the problem:
7(5v-2)(7v+3)=0
First we would need to get rid of that 7, to do that, we would divide both sides of the equation by 7. Because anything divided by 0 and 0 divided by anything is 0, the 7 would just be eliminated:
(5v-2)(7v+3)=0
Now we make each equation equal to 0:
5v-2=0
7v+3=0
Now solve for v:
v=2/5
v=-3/7
These are the two answers. Hope this helped!