Answer: The height of the ball (in meters) after t seconds is given by the equation h = 2 + 5t - 5t^2. We can use this equation to find the values of t for which the ball's height is 3 meters.
We need to find the values of t that make h = 3, so we can substitute 3 for h in the equation:
3 = 2 + 5t - 5t^2
Then we can solve for t by moving all the terms to one side of the equation and factoring it:
-5t^2 + 5t - 1 = 0
And we can use the quadratic formula to find the solutions of this equation:
t = (5 +/- sqrt(5^2 - 4*(-1)(-1)))/ 2(-1)
t = (5 +/- sqrt(25 + 4))/ -2
t = (5 +/- sqrt(29))/ -2
The solutions of this equation are t = (5 +/- sqrt(29))/ -2
Since the time, t, is a real value the square root of 29 should be positive.
The values of t for which the ball's height is 3 meters are not real values, so there's no time when the ball's height is 3 meters.
Explanation: