Answer: To solve the equation -3(x+2)^2-4 = 5 by factoring, we can follow these steps:
Move all the terms to one side of the equation by adding 3(x+2)^2 and 4 to both sides: -3(x+2)^2-4+3(x+2)^2+4 = 5+3(x+2)^2
Combine like terms: 3(x+2)^2 = 5
Take the square root of both sides of the equation: (x+2)^2 = 5/3
Isolate x+2 on one side of the equation by taking the square root of both sides: x+2 = ±sqrt(5/3)
Solve for x by subtracting 2 from both sides of the equation: x = ±sqrt(5/3) - 2
So the solutions to the equation -3(x+2)^2-4 = 5 by factoring is x = ±sqrt(5/3) - 2.
It's important to note that the square root of a fraction is a positive and negative solution, so the solutions are x = sqrt(5/3) - 2 and x = -sqrt(5/3) - 2
Explanation: