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Find the surface area of a square pyramid with side length 2 m and slant height 3 m.​

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Answer: The surface area of a square pyramid with a side length of 2m and slant height of 3m is 12 square meters.

Explanation:

The surface area of a square pyramid can be calculated using the formula:

Surface area = Base area + 4 * (Area of one of the lateral faces)

The base area of the pyramid is the area of the square base, which is the side length squared: 2m * 2m = 4m^2

To find the area of one of the lateral faces, we can use the Pythagorean theorem to find the length of the face, which is the hypotenuse of a right triangle with the slant height and half of the side length as the other two sides.

so, (1/2 * 2m)^2 + 3^2 = x^2

x= (1/2 * 2m)^2 + 3^2

x = 2

Therefore, the surface area of the pyramid is:

Surface area = 4m^2 + 4 * 2m^2 = 4m^2 + 8m^2 = 12m^2

So, the surface area of a square pyramid with a side length of 2m and a slant height of 3m is 12 square meters.

User Colin Pickard
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