Question

An air traffic controller is taking two planes. To start plane a is at an altitude of 2457 feet and plane B is just taking off. Plane eight is gaining altitude at 25.25 ft./s in plane, B is gaining altitude at 70.75 ft./s, how many seconds will pass before the planes are at the same altitude and what will they are out of to be when they’re at that same altitude

Answer 1

Answer: To find the number of seconds it takes for the planes to reach the same altitude, we can use the following formula:

time = (difference in altitude) / (rate of plane B - rate of plane A)

In this case, the difference in altitude is the altitude of plane A (2457 feet) and plane B is just taking off so its altitude is 0 feet.

So, substituting these values into the formula:

time = (2457) / (70.75 - 25.25)

time = 2457 / 45.5

time = 53.7 seconds

So it takes 53.7 seconds for the planes to reach the same altitude. To find out what altitude they will be at when they reach the same altitude, we can use the formula:

Altitude = (rate of plane A x time) + altitude of plane A

Substituting the values we have:

Altitude = (25.25 x 53.7) + 2457

Altitude = 1351.6 + 2457

Altitude = 3809.6 ft

So, both planes will be at 3809.6 ft. when they reach the same altitude.

Explanation: