Reaction of O₂ with HCl is as follow,
4 HCl + O₂ → 2 H₂O + 2 Cl₂
Let suppose we are given with 1 mole of HCl gas, Then,
According to eq,
89.6 L (4 moles) of HCl when reacted produced = 44.8 L (2 moles) Cl₂ gas
So,
22.4 L (1 mole) of HCl will produce = X L of Cl₂ gas
Solving for X,
X = (22.4 L × 44.8 L) ÷ 89.6 L
X = 11.2 L of Cl₂ Gas